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Mecaflux Crack Torrent.rar Download Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar Mecaflux 2012 TORRENT.rar Mecaflux 2012 TORRENT.rar Mecaflux 2012 TORRENT.rar Mecaflux 2012 TORRENT.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar Mecaflux 2012 TORRENT.rar.rar M Mecaflux Heliciel.rarQ: Parsing a complex input in Python I've got an input as a string that is like #FirstSection#LetsTakeThisAsADictString ['a:1:{s:5:"name";s:5:"b";}','c:1:{s:5:"name";s:4:"xyz";}'] I'm trying to get the dict values out of it using regex, like >>> re.findall(r'(\w+):(\d+);', myStr) ['a:1:{s:5:"name";s:5:"b";}','c:1:{s:5:"name";s:4:"xyz";}'] But I'm now finding that it is also capturing this in the first section and i'm getting an extra [', '] at the start and end. So, I'm looking for something that will just get me the dict values as strings. I'm using regex because it works, but I'm wondering if I can do this without regex. I was hoping to just do, something like >>> re.findall(':\w+', myStr) ['a:1:{s:5:"name";s:5:"b";}','c:1:{s:5:"name";s:4:"xyz";}'] But obviously that won't work because of the [', '] in front of the dict values. A: You can't use regex to remove the starting and ending square brackets. You'll need to do some string slicing: import re match = re.findall(r'(\w+):(\d+);', myStr) first_section = myStr[0:myStr.index(' ')] second_section = myStr[myStr.index(' ')+1:] print 'first:', first_section print'second:', second_section [], [], [], [], [], [], [], [], 1cdb36666d


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